solve for x:

1. log_x+1(x² + x - 6)² = 4
2. log₅120 + (x - 3) – 2.log₅(1 – 5^x-3) = -log₅(0.2 – 5^x-4)

logx+1(x2+ x – 6)2= 4
It can be written as = (x2+ x – 6)2 = x+1 ^4
Solve this and find x

Also use
Log Rules:
1) logb(mn) = logb(m) + logb(n)
2) logb(m/n) = logb(m) – logb(n)
3) logb(mn) = n · logb(m)